2019.02 JAVA 剪刀石頭布－驢子的生活日記

題目

寫一個三人的剪刀石頭布遊戲（其中一個可以由自己輸入）

package ch5;
import java.io.*;
public class ch5_18
{
   public static void main(String args[])throws IOException
   {/*題目說可以自己出,全部電腦出來省時間
       InputStreamReader in=new InputStreamReader(System.in);
       BufferedReader buf=new BufferedReader(in);
   */
       int a,b,c;
       String sa="未知",sb="未知",sc="未知",res="無法判斷";
       System.out.println("輸入0等於剪刀1等於石頭2等於布");
   /*
       String sa;
       sa=buf.readLine();
       a=Integer.parseInt(sa);
   */
       a=(int)(Math.floor(Math.random()*3));
       b=(int)(Math.floor(Math.random()*3));
       c=(int)(Math.floor(Math.random()*3));

       switch (a)
       {
       case 0:
           sa="剪刀";
           break;
       case 1:
           sa="石頭";
           break;
       case 2:
           sa="布";
           break;
       }
       switch (b)
       {
       case 0:
           sb="剪刀";
           break;
       case 1:
           sb="石頭";
           break;
       case 2:
           sb="布";
           break;
       }
       switch (c)
       {
       case 0:
           sc="剪刀";
           break;
       case 1:
           sc="石頭";
           break;
       case 2:
           sc="布";
           break;
       }
       /*以上拉出來判斷出的東西*/
       switch (a)
       {
       case 0:
           switch (b)
           {
           case 0:
               switch (c)
               {
               case 0:
                   res = "平手在猜一次";
                   break;
               case 1:
                   res = "C獲勝";
                   break;
               case 2:
                   res = "A和B換勝";
                   break;
               }
           break;
           case 1:
               switch (c)
               {
               case 0:
                   res = "B獲勝";
                   break;
               case 1:
                   res = "B和C獲勝";
                   break;
               case 2:
                   res = "在猜一次";
                   break;
               }
           break;
           case 2:
               switch (c)
               {
               case 0:
                   res = "A和C獲勝";
                   break;
               case 1:
                   res = "在猜一次";
                   break;
               case 2:
                   res = "A獲勝";
                   break;
               }
           break;
           }
       break;
       case 1:
           switch (b)
           {
           case 0:
               switch (c)
               {
               case 0:
                   res = "A獲勝";
                   break;
               case 1:
                   res = "A和C獲勝";
                   break;
               case 2:
                   res = "在猜一次";
                   break;
               }
           break;
           case 1:
               switch (c)
               {
               case 0:
                   res = "C獲勝";
                   break;
               case 1:
                   res = "平手在猜一次";
                   break;
               case 2:
                   res = "C獲勝";
                   break;
               }
           break;
           case 2:
               switch (c)
               {
               case 0:
                   res = "在猜一次";
                   break;
               case 1:
                   res = "B獲勝";
                   break;
               case 2:
                   res = "B和C獲勝";
                   break;
               }
           break;
           }
       break;
       case 2:
           switch (b)
           {
           case 0:
               switch (c)
               {
               case 0:
                   res = "B和C獲勝";
                   break;
               case 1:
                   res = "在猜一次";
                   break;
               case 2:
                   res = "B獲勝";
                   break;
               }
           break;
           case 1:
               switch (c)
               {
               case 0:
                   res = "在猜一次";
                   break;
               case 1:
                   res = "A獲勝";
                   break;
               case 2:
                   res = "A和C獲勝";
                   break;
               }
           break;
           case 2:
               switch (c)
               {
               case 0:
                   res = "C獲勝";
                   break;
               case 1:
                   res = "A和B獲勝";
                   break;
               case 2:
                   res = "平手在猜一次";
                   break;
               }
           break;
           }

       break;
       }
       System.out.println("結果是"+res+",A和B和C分別出"+sa+","+sb+","+sc);
   }
}